Write the equation of the ellipse, knowing it’s center C ( 2 , 1 ) and the ends

xonycutieoxl1

xonycutieoxl1

Answered question

2022-06-07

Write the equation of the ellipse, knowing it’s center C ( 2 , 1 ) and the ends of two conjugate diameters A ( 5 , 1 ), B ( 0 , 3 ) .

Answer & Explanation

Korotnokby

Korotnokby

Beginner2022-06-08Added 19 answers

Step 1
The parametric equation of the ellipse using its conjugate radii C A , C B is
P ( t ) = C + cos t C A + sin t C B ( 1 )
In matrix-vector form, let P = [ x , y ] T , C = [ 2 , 1 ] T then C A = [ 3 , 0 ] T and C B = [ 2 , 2 ] T and u = [ cos t , sin t ] T , the above equation becomes
P C = G u ( 2 )
where G = [ 3 2 0 2 ]
From equation (2) we have
u = G 1 ( P C ) ( 3 )
And since cos 2 t + sin 2 t = 1 , then u T u = 1 , hence,
( P C ) T G T G 1 ( P C ) = 1 ( 4 )
And this is the equation of the ellipse. For numerical evaluation, we have
G 1 = 1 6 [ 2 2 0 3 ]
Thus
G T G 1 = 1 36 [ 4 4 4 13 ]
so that the equation of the ellipse (4) becomes
4 ( x 2 ) 2 + 8 ( x 2 ) ( y 1 ) + 13 ( y 1 ) 2 = 36

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