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Draw a right-angled triangle ABC where B is 90 deg, A is θ.cot(θ)=ABBC=7.AC=72+1=52.AB=7,BC=1.
sec(θ)=1cos(θ)=527=1.0102. These are all approximate values and apply to quadrant 1. cot(θ)=71 in quadrant 1, or −7−1 in quadrant 3. In this quadrant sin, cos, sec are all negative, so sin(θ)=−0.1414,cos(θ)=−0.9899,sec(θ)=−1.0102 in QIII, and 0.1414, 0.9899, 1.0102 in QI.
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