Solve for x
$1200{\left(1.03\right)}^{x}=800{\left(1.08\right)}^{x}$

FobelloE
2020-11-08
Answered

Solve for x
$1200{\left(1.03\right)}^{x}=800{\left(1.08\right)}^{x}$

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Jozlyn

Answered 2020-11-09
Author has **85** answers

divide by 800 on both sides

divide by

Exact:

Decimal, approximate: x = about 8.554

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Evaluating a limit with variable in the exponent

For$\underset{x\to \mathrm{\infty}}{lim}{(1-\frac{2}{x})}^{\frac{x}{2}}$

I have to use the L'Hospital"s rule, right? So I get:

$\underset{x\to \mathrm{\infty}}{lim}\frac{x}{2}\mathrm{log}(1-\frac{2}{x})$

And what now? I need to take the derivative of the log, is it:$\frac{1}{1-\frac{2}{x}}$ but since there is x, I need to use the chain rule multiply by the derivative of $\frac{x}{2}$ ?

For

I have to use the L'Hospital"s rule, right? So I get:

And what now? I need to take the derivative of the log, is it:

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$3{x}^{2}+5x+14=0$

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The arithmetic mean (average) of two numbers c and d is given by $\stackrel{\u2015}{x}=\frac{c+d}{2}$

The value$\stackrel{\u2015}{x}$ is equidistant between c and d, so the sequence c,$\stackrel{\u2015}{x}$ , d is an arithmetic sequence. inserting k equally spaced values between c and d, yields the arithmetic sequence $c,{\stackrel{\u2015}{X}}_{1},{\stackrel{\u2015}{X}}_{2},{\stackrel{\u2015}{X}}_{3},{\stackrel{\u2015}{X}}_{4},...,{\stackrel{\u2015}{X}}_{k},d$ . Use this information for Exercise.

Insert four arithmetic means between 19 and 64.

The value

Insert four arithmetic means between 19 and 64.

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While using Cost-benefit analysis which of the following is a true statement.

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b) It will always produce a recommendation consistent with the present worth, future worth, and annual worth methods.

c) It can be used only to evaluate projects from the public sector (such as bridges and roadways).

d) None of the above.

a) It will always produce a recommendation consistent with the simple payback period method.

b) It will always produce a recommendation consistent with the present worth, future worth, and annual worth methods.

c) It can be used only to evaluate projects from the public sector (such as bridges and roadways).

d) None of the above.

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$\mathrm{ln}\left(\frac{x}{\sqrt{{x}^{2}+1}}\right)$