# Solve sqrt(16-x^2) between -4 and 0

Question
Differential equations
Solve $$\displaystyle\sqrt{{{16}-{x}^{{2}}}}$$ between -4 and 0

2021-02-11
Definite integral of $$\displaystyle\sqrt{{{16}-{x}^{{2}}}}$$ between -4 and 0
Okay, you are looking at half of a circle.
Diameter is 4. So radius is 2.
You are finding an area, the formula is $$\displaystyle{A}=\pi\cdot{r}^{{2}}$$
$$\displaystyle{A}=\pi{2}^{{2}}={4}\pi$$

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