# log3(x + 3) − log3(x − 3) = 2

$\mathrm{log}3\left(x+3\right)-\mathrm{log}3\left(x-3\right)=2$
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$\mathrm{log}3\left(x+3\right)-\mathrm{log}3\left(x-3\right)=2$
$\mathrm{log}3\left[\frac{x+3}{x-3}\right]=2$
$\frac{x+3}{x-3}={3}^{2}=9$
$x+3=9\cdot \left(x-3\right)$
or $\left(x+3\right)-9\cdot \left(x-3\right)=0$
$x=3.75$