# How to solve 8(3a+y)=9(2a-4)?

How to solve $8\left(3a+y\right)=9\left(2a-4\right)$?

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$8\left(3a+y\right)=9\left(2a-4\right)$
$8×3a+8y=9×2a-9×4$
$24a+8y=18a-36$
$8y=18a-24a-36$
$8y=-6a-36$
$y=-6\frac{a}{8}-\frac{36}{8}$
$y=-3\frac{a}{4}-\frac{9}{2}$

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