Find the general solution:
$1-\frac{{\mathrm{tan}}^{2}\left(x\right)}{1}+{\mathrm{tan}}^{2}\left(x\right)=1-2{\mathrm{sin}}^{2}\left(x\right)$

Aneeka Hunt
2020-10-23
Answered

Find the general solution:
$1-\frac{{\mathrm{tan}}^{2}\left(x\right)}{1}+{\mathrm{tan}}^{2}\left(x\right)=1-2{\mathrm{sin}}^{2}\left(x\right)$

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doplovif

Answered 2020-10-24
Author has **71** answers

therefore

then make the fractions of the top and bottom common by timeing by cosx therefore

therefore

therefore

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