Find the general solution: 1-tan^2(x)/1+tan^2(x)=1-2sin^2(x)

Aneeka Hunt 2020-10-23 Answered
Find the general solution: 1tan2(x)1+tan2(x)=12sin2(x)
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Expert Answer

doplovif
Answered 2020-10-24 Author has 71 answers
tan2x=sin2xcos2xandcos2=1sin2xandcos2x+sin2x=1
therefore 1sin2xcos2x1+(sin2xcos2x)
then make the fractions of the top and bottom common by timeing by cosx therefore
cos2xsin2xcos2x+sin2x
therefore
cos2xsin2x1=cos2xsin2x
cos2=1sin2
therefore
(1sin2x)sin2x=12sin2x
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