If cosx= -12/13 and csc x<0, find cot(2x)

floymdiT 2021-02-25 Answered

If cosx=1213andcscx<0,
find cot(2x)

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Expert Answer

Demi-Leigh Barrera
Answered 2021-02-26 Author has 97 answers

cot(2x)=cos(2x)sin(2x)=12(sin(x))22sin(x)cos(x).
In the right-angled triangle ABC drawn on x-y axis, A is point (-12,0), B is (0,0) and C is (0,-5).
Angle ABC is a right-angle and BAC=x.
cos(x)=ABAC=1213.BC=AC2AB2=132122=25=5.
sin(x)=BCAC=513(cosec(x)<0).cot(2x)=(12251692(513)(1213)=16950120=119120).

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