I am having trouble understanding the relatioship between rows and columns of a matrix. Say, the fo

Denisse Valdez

Denisse Valdez

Answered question

2022-05-30

I am having trouble understanding the relatioship between rows and columns of a matrix.
Say, the following homogeneous system has a nontrivial solution.
3 x 1 + 5 x 2 4 x 3 = 0 3 x 1 2 x 2 + 4 x 3 = 0 6 x 1 + x 2 8 x 3 = 0
Let A be the coefficient matrix and row reduce [A0] to row-echelon form:
[ 3 5 4 0 3 2 4 0 6 1 8 0 ] [ 3 5 4 0 0 3 0 0 0 0 0 0 ]
a 1 a 2 a 3
Here, we see x 3 is a free variable and thus we can say 3rd column, a 3 , is in span ( a 1 , a 2 )
But what does it mean for an echelon form of a matrix to have a row of 0's?
Does that mean 3rd row can be generated by 1st & 2nd rows?
just like 3rd column can be generated by 1st & 2nd columns?
And this raises another question for me, why do we mostly focus on columns of a matrix?
because I get the impression that ,for vectors and other concepts, our only concern is
whether the columns span R n or the columns are linearly independent and so on.
I thought linear algebra is all about solving a system of linear equations,
and linear equations are rows of a matrix, thus i think it'd be logical to focus more on rows than columns. But why?

Answer & Explanation

humanistex3

humanistex3

Beginner2022-05-31Added 9 answers

Having a row of 0's in the row-echelon form means that we were able to write the third row of A as a linear combination of the second and first rows. As it so happens for square matrices, this is true precisely when we can write the columns as a linear combination of each other (that is, when the columns are not linearly independent). If you further reduce this to reduced row-echelon form, you get
[ 1 0 4 / 3 0 0 1 0 0 0 0 0 0 ]
Because the third column lacks a pivot, X 3 is our free variable, which means that we can write a 3 as a linear combination of the other two columns.
There's a very good reason for focusing on the columns of a matrix. This comes out of using A as a linear transformation, where the "column space" gives us the "range" of the function f ( x ) = A x .

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