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Davin Fields

Davin Fields

Answered question

2022-05-31

Eliminate θ from the equation
x cos ( 3 θ ) + y sin ( 3 θ ) = a cos ( θ ) x sin ( 3 θ ) + y cos ( 3 θ ) = a cos ( θ + π 6 )
I tried squaring a adding but got nowhere. Also got x and y as linear equations in form of θ but cant see what to do next.

Answer & Explanation

Bettoldi1l

Bettoldi1l

Beginner2022-06-01Added 7 answers

Not elegant at all!
Squaring & adding
x 2 + y 2 + 2 x y sin 6 θ a 2 = cos 2 θ + cos 2 ( θ + π 6 ) = 1 + cos π 6 cos ( 2 θ + π 6 )         ( 1 )
using Prove that cos ( A + B ) cos ( A B ) = cos 2 A sin 2 B
Adding & squaring
( x + y ) 2 ( 1 + sin 6 θ ) a 2 = [ cos θ + cos ( θ + π 6 ) ] 2 = ( 1 + cos π 6 ) ( 1 + cos ( 2 θ + π 6 ) )         ( 2 )
using Prosthaphaeresis Formula cos C + cos D and Double angle formula
2 θ + π 6 = t , 6 θ = 3 t π 2
From (1),
x 2 + y 2 2 x y cos 3 t a 2 = 1 + cos π 6 cos t         ( 3 )
From (2),
( x + y ) 2 ( 1 cos 3 t ) a 2 = ( 1 + cos π 6 ) ( 1 + cos t )         ( 4 )
Solve (3),(4) for cos t , cos 3 t
and use cos 3 t = 4 cos 3 t 3 cos t to eliminate t

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