# How to solve x^2 - 6x + 9 = 20 using the Square Root Property

How to solve ${x}^{2}-6x+9=20$ using the Square Root Property
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SchepperJ
${x}^{2}-6x+9=20$ factor the left side ${\left(x-3\right)}^{2}=20$ now take the square root of each side $x-3=+\phantom{\rule{1em}{0ex}}\text{or}\phantom{\rule{1em}{0ex}}-\sqrt{20}$ $x=\sqrt{20}+3\phantom{\rule{1em}{0ex}}\text{or}\phantom{\rule{1em}{0ex}}x=-\sqrt{20}-3$ $x=2\sqrt{5}+3\phantom{\rule{1em}{0ex}}\text{or}\phantom{\rule{1em}{0ex}}x=-2\sqrt{5}-3$