How to solve x^2 - 6x + 9 = 20 using the Square Root Property

Question
Equations
asked 2020-11-29
How to solve \(\displaystyle{x}^{{2}}-{6}{x}+{9}={20}\) using the Square Root Property

Answers (1)

2020-11-30
\(\displaystyle{x}^{{2}}-{6}{x}+{9}={20}\) factor the left side \(\displaystyle{\left({x}-{3}\right)}^{{2}}={20}\) now take the square root of each side \(\displaystyle{x}-{3}=+{\quad\text{or}\quad}-\sqrt{{{20}}}\) \(\displaystyle{x}=\sqrt{{{20}}}+{3}{\quad\text{or}\quad}{x}=-\sqrt{{{20}}}-{3}\) \(\displaystyle{x}={2}\sqrt{{{5}}}+{3}{\quad\text{or}\quad}{x}=-{2}\sqrt{{{5}}}-{3}\)
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