I have seen it stated that for an open subset Y &#x2286;<!-- ⊆ --> X such that X i

Trevor Wood

Trevor Wood

Answered question

2022-05-31

I have seen it stated that for an open subset Y X such that X is a compact Hausdorff space we get an identification of the C -algebras : C ( X Y ) C ( X ) / C 0 ( Y ).
I suppose that this relies on the Tietze extension theorem but I fail to connect the dots.
How do I realize this?

Answer & Explanation

Conor Frederick

Conor Frederick

Beginner2022-06-01Added 7 answers

Because Y is open, X Y is compact. Tietze's extension theorem applies and given f C ( X Y ) there exists f ~ C ( X ) with f ~ | X Y = f and f ~ = f .
The natural thing seems to define a -epimorphism C ( X ) C ( X Y ) such that its kernel is C 0 ( Y ). That is we consider γ : C ( X ) C ( X Y ) to be the restriction map. Tietze's Extension Theorem, as mentioned above, guarantees that γ is surjective. Is is straightforward that it is a -homomorphism.
Finally, if γ ( f ) = 0, then f | X Y = 0. So f is continuous on Y and takes the value 0 on Y. This means that the restriction of f to Y is in C 0 ( Y ); indeed, given ε > 0, the open set V = | f | 1 [ 0 , ε ) is open and contains X Y, and its complement is a compact subset of Y such that | f | < ε outside of it.

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