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cos(2x)=2cos2(x)−1 2cos2(x)−1=cos(x) 2cos2(x)−1−cos(x)=0 2cos2(x)−cos(x)−1=0 (2cos(x)+1)(cos(x)−1)=0 2cos(x)+1=0 2cos(x)=−1 cos(x)=−12 x=cos−1(−12) x=π/3[2π−π/3=5π/3] x=π/3 and 5π/3 cos is positive in the first and fourth quadrant. cos(x)−1=0 cos(x)=1 x=cos−1(1) x=0,2π
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If sinx=ey,0<x<π, what is dy/dx in terms of x? (A) −tanx (B) −cotx (C) cotx (D) tanx (E) cscx
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