How do i show this equality without using reccurence method: <munderover> &#x220F;<!-- ∏ --

res2bfitjq

res2bfitjq

Answered question

2022-05-28

How do i show this equality without using reccurence method: k = 0 k = n cos θ 2 k = sin θ 2 n sin ( 2 n θ ) ?

Answer & Explanation

hoffwnbu

hoffwnbu

Beginner2022-05-29Added 13 answers

First, notice that:
2 cos x sin x = sin 2 x cos x = 1 2 sin 2 x sin x
Then, given an integer number n>0 we have
cos ( θ 2 ) cos ( θ 2 2 ) cos ( θ 2 n ) = 1 2 n sin ( θ ) sin ( θ 2 ) sin ( θ 2 ) sin ( θ 2 2 ) sin ( θ 2 n 1 ) sin ( θ 2 n )
Which is a "telescopic product", and the inequality follows from here.

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