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aniawnua

aniawnua

Answered question

2022-05-29

Let μ be a complex measure on R n and f , g L 1 ( μ ) such that 0 < f ( x ) g ( x ) for a.e. x R n . Then is it true that
| R n f d μ | | R n g d μ |  ? 

I was trying to break each integral first in its real and imaginary part and then their corresponding positive and negative parts, i.e.
R n f d μ = R e ( R n f d μ ) + i I m ( R n f d μ )
= R e + ( R n f d μ ) R e ( R n f d μ ) + i I m + ( R n f d μ ) i I m ( R n f d μ )
and then wanted to look at corresponding decompositions of the measure and the integral R n g d μ and obtain inequalities. But I can't figure them out and proceed from here.
Can someone please help?

Answer & Explanation

Fahrleine9m

Fahrleine9m

Beginner2022-05-30Added 11 answers

If μ = δ 0 δ 1 then the inequality becomes | f ( 0 ) f ( 1 ) | | g ( 0 ) g ( 1 ) | . Can you come with an example where 0 < f g but this inequality fails? [ Make RHS 0].
[Notation: δ x ( E ) = 1 if x E and 0 otherwise].

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