# Using substitution method solve 3x+4y=7 2x-3y=-1

Using substitution method solve
$3x+4y=7$
$2x-3y=-1$
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Faiza Fuller
From the second equation, $2x=3y-1$, so $x=\frac{3y-1}{2}.$
Substitute for x in the first equation:
$3\frac{3y-1}{2}+4y=7$, multiply each side by 2:
$3\left(3y-1\right)+8y=14,9y-3+8y=14,17y=17,y=1,$ therefore $x=\frac{3-1}{2}=\frac{2}{2}=1$.
Solution: x=1, y=1.