Find an equation of the tangent line to the curve at the given point. y=sin(sinx) , (2pi,0)

DofotheroU 2021-01-19 Answered
Find an equation of the tangent line to the curve at the given point.
y=sin(sinx),(2π,0)
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Expert Answer

Cristiano Sears
Answered 2021-01-20 Author has 96 answers
The derivative y=cosxcos(sinx) by the product rule.
At x=2(π),y=cos(0)cos(0)=1,sin(2(π))=0.
Therefore 1 is the slope of the tangent and the slope of the tangent line y=x+b, where b is the y intercept.
Putting in the point (2(π),0):0=2(π)+b,sob=2(π)andy=x2(π).
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