Which rules are used to make function like one in Laplace Transformations table? I have function li

dglennuo

dglennuo

Answered question

2022-05-28

Which rules are used to make function like one in Laplace Transformations table?
I have function like this:
s 2 + 3 s + 3 ( 2 s 2 + 7 s + 7 )
It needs to be brought to the level of Laplace Transformations from table, like these two:
a ( s b ) 2 + a 2
s b ( s b ) 2 + a 2
I have the solution for this problem, but I can't figure out the logic behind it. Steps included are:
1 2 0.5 s + 0.5 2 s 2 + 7 s + 7 = 1 2 0.5 s + 0.5 ( s + 1.75 ) 2 + 0.6614 2 = 1 2 0.5 s + 1.75 ( s + 1.75 ) 2 + 0.6614 2 + ( 0.5 1.75 0.5 ) 1 0.6614 0.6614 ( s + 1.75 ) 2 + 0.6614 2

Answer & Explanation

thoumToofwj

thoumToofwj

Beginner2022-05-29Added 16 answers

I have outlined the logic of the calculations step by step below. However, your solution seems to have slight problems.
s 2 + 3 s + 3 ( 2 s 2 + 7 s + 7 ) = s 2 + 3 s + s / 2 s / 2 + 3 + 1 / 2 1 / 2 ( 2 s 2 + 7 s + 7 ) = s 2 + 3 s + s / 2 s / 2 + 3 + 1 / 2 ( 2 s 2 + 7 s + 7 ) s / 2 + 1 / 2 ( 2 s 2 + 7 s + 7 ) = 1 2 1 2 s + 1 ( 2 s 2 + 7 s + 7 ) = 1 2 1 4 s + 1 ( s 2 + 7 s / 2 + 7 / 2 ) = 1 2 1 4 s + 1 ( s 2 + 2 × 7 / 4 × s + 7 / 2 ) = 1 2 1 4 s + 1 ( s 2 + 2 × 7 / 4 × s + ( 7 / 4 ) 2 ( 7 / 4 ) 2 + 7 / 2 ) = 1 2 1 4 s + 1 ( s + 7 / 4 ) 2 ( 7 / 4 ) 2 + 7 / 2 ) = 1 2 1 4 s + 1 ( s + 1.75 ) 2 ( 1.75 ) 2 + 3.5 = 1 2 1 4 s + 1 ( s + 1.75 ) 2 + 0.4375 = 1 2 1 4 s + 1 ( s + 1.75 ) 2 + ( 0.6614 ) 2 = 1 2 1 4 s + 1 + 0.75 0.75 ( s + 1.75 ) 2 + ( 0.6614 ) 2 = 1 2 1 4 s + 1.75 ( s + 1.75 ) 2 + ( 0.6614 ) 2 + 1 4 0.75 ( s + 1.75 ) 2 + ( 0.6614 ) 2 = 1 2 1 4 s + 1.75 ( s + 1.75 ) 2 + ( 0.6614 ) 2 + 1 4 0.75 × 0.6614 ÷ 0.6614 ( s + 1.75 ) 2 + ( 0.6614 ) 2 = 1 2 1 4 s + 1.75 ( s + 1.75 ) 2 + ( 0.6614 ) 2 + 1.13 4 0.6614 ( s + 1.75 ) 2 + ( 0.6614 ) 2
cricafh

cricafh

Beginner2022-05-30Added 3 answers

s 2 + 3 s + 3 ( 2 s 2 + 7 s + 7 ) = 1 2 2 s 2 + 6 s + 6 ( 2 s 2 + 7 s + 7 ) = 1 2 ( 2 s 2 + 7 s + 7 ) ( s + 1 ) ( 2 s 2 + 7 s + 7 ) = 1 2 1 2 s + 1 2 s 2 + 7 s + 7 = 1 2 1 4 s + 1 s 2 + ( 7 / 2 ) s + ( 7 / 2 ) = 1 2 1 4 s + 1 ( s + 7 / 4 ) 2 + ( 7 / 2 ) ( 49 / 16 ) = 1 2 1 4 s + ( 7 / 4 ) ( 3 / 4 ) ( s + 7 / 4 ) 2 + 7 / 16 = 1 2 1 4 s + 7 / 4 ( s + 7 / 4 ) 2 + 7 / 16 + 3 16 1 ( s + 7 / 4 ) 2 + 7 / 16 = 1 2 1 4 s + 7 / 4 ( s + 7 / 4 ) 2 + 7 / 16 + 3 16 1 ( s + 7 / 4 ) 2 + 7 / 16 = 1 2 1 4 s + 7 / 4 ( s + 7 / 4 ) 2 + ( 7 4 ) 2 + 3 16 1 ( s + 7 / 4 ) 2 + ( 7 4 ) 2 1 2 1 4 s + 7 / 4 ( s + 7 / 4 ) 2 + ( 7 4 ) 2 + 3 7 28 7 4 ( s + 7 / 4 ) 2 + ( 7 4 ) 2

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