Condense them to the same base before solving for x log16 (x) +log4 (x) +log2 (x) =7

Aneeka Hunt 2020-10-20 Answered
Condense them to the same base before solving for x log16(x)+log4(x)+log2(x)=7
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Brighton
Answered 2020-10-21 Author has 103 answers
log16(x)=(14)log2(x)
log4(x)=(12)log2(x)
so you hav (1+12+14)log2(x)=7
1.75log2(x)=7
log2(x)=71.75=4
x=24=16
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