# Condense them to the same base before solving for x log16 (x) +log4 (x) +log2 (x) =7

Aneeka Hunt 2020-10-20 Answered
Condense them to the same base before solving for x $\mathrm{log}16\left(x\right)+\mathrm{log}4\left(x\right)+\mathrm{log}2\left(x\right)=7$
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## Expert Answer

Brighton
Answered 2020-10-21 Author has 103 answers
$\mathrm{log}16\left(x\right)=\left(\frac{1}{4}\right)\mathrm{log}2\left(x\right)$
$\mathrm{log}4\left(x\right)=\left(\frac{1}{2}\right)\mathrm{log}2\left(x\right)$
so you hav $\left(1+\frac{1}{2}+\frac{1}{4}\right)\mathrm{log}2\left(x\right)=7$
$1.75\cdot \mathrm{log}2\left(x\right)=7$
$\mathrm{log}2\left(x\right)=\frac{7}{1.75}=4$
$x={2}^{4}=16$
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