Removing additive factors from the denominator of a fraction Suppose I have a variable x

Emery Boone

Emery Boone

Answered question

2022-05-21

Removing additive factors from the denominator of a fraction
Suppose I have a variable x L defined as follows:
x L = r 1 e t 0 s s + r 2 + r 3 ,
Is there a way for me to rearrange this fraction to get something in this form
x L = [ stuff ] [ stuff ] s ,
where " " is any operator (e.g., + or ×)?

Answer & Explanation

Kaelyn Barrett

Kaelyn Barrett

Beginner2022-05-22Added 5 answers

This is what I wanted:
x L = r 1 e t 0 s s ( 1 1 + r 2 / s + r 3 / s ) x L = r 1 e t 0 s s ( s s + r 2 + r 3 ) x L = r 1 e t 0 s s ( 1 s + r 2 + r 3 ) s x L = r 1 e t 0 s ( 1 s + r 2 + r 3 )

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?