Solve log4(x+3)+log4(2-x)=1

Dolly Robinson 2021-01-10 Answered

Solve

\log 4 (x + 3) + \log 4 (2 - x) = 1

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Expert Answer

Arnold Odonnell

Answered 2021-01-11 Author has 109 answers

\log 4 (x + 3) + \log 4 (2 - x) = 1

\log 4 [(x + 3) \cdot (2 - x)] = 1

(x + 3) \cdot (2 - x) = 4

- x^{2} - x + 6 = 4

- x^{2} - x + 2 = 0 or x^{2} + x - 2 = 0

(x - 1) (x + 2) = 0

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