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Let P(x, y) be the terminal point on the unit circle determined by t. Then sint=,cost=, and tant=.
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I have been trying to do this problem: Solve sec(x)=tan(x), 0≤x<2π I started by rewriting sec(x) as 1cos(x). I then rewrote tan(x) to get sin(x)cos(x) Therefore: 1cosx=sinxcosx Therefore: 1=sinx,x=π2 However, this is not a solution to the original problem because both y=tan(x) and y=sec(x) have asymptotes as x=π2
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