# Solve 2sin^2x=1

Solve $2{\mathrm{sin}}^{2}x=1$
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Macsen Nixon
$x=\frac{3\cdot \pi \cdot n}{4}\phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}\frac{5\cdot \pi \cdot n}{4}$
for n any integer