Deterrmine the first derivative (dy/dx) : y= 2e^2x + In x^3 - 2e^x

ringearV 2020-11-22 Answered
Deterrmine the first derivative (dydx) :
y=2e2x+Inx32ex
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Expert Answer

Laith Petty
Answered 2020-11-23 Author has 103 answers

dydx=4e2x+3x2ex
(ln(x3)=3ln(x)anddiferential of e2x=2e2x).

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