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meindwrhc

meindwrhc

Answered question

2022-05-23

Let ( Ω , μ ) be a σ-finite measure space. Suppose 1 p < . Consider the cone L p ( Ω ) + of positive functions of L p ( Ω ).
Is L p ( Ω ) + weak-closed in L p ( Ω ) ?

Answer & Explanation

nifeonibonitozg

nifeonibonitozg

Beginner2022-05-24Added 12 answers

For p > 1, L p is reflexive and this set is convex so it is weakly closed because it is norm-closed (Mazur's lemma).
In L 1 , suppose that ( f n ) n = 1 is a sequence of non-negative functions converging weakly to f. Suppose that f is strictly negative on a set A of positive measure. Let g be the indicator function of A. We have
Ω f n g = A f n Ω f g = A f < 0.
This is impossible as f n are non-negative. This argument will work in L p too, so Mazur's lemma is not quite necessary.

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