How to evaluate this limit? <munder> <mo movablelimits="true" form="prefix">lim <mrow

realburitv4

realburitv4

Answered question

2022-05-22

How to evaluate this limit? lim x 0 ln ( cos x 1 + sin x ) 1 x

Answer & Explanation

rass1k6s

rass1k6s

Beginner2022-05-23Added 13 answers

Using L'Hopital's Rule, we have
lim x 0 ln ( cos x 1 + sin x ) 1 / x = lim x 0 ln ( cos x ) ln ( 1 + sin x ) x = lim x 0 ( tan x cos x 1 + sin x ) = 1

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?