# Solve below log Equation, this equation came with different bases:log2(x+2)-3*log8(x+3)=2

Solve below log Equation, this equation came with different bases: $\mathrm{log}2\left(x+2\right)-3\cdot \mathrm{log}8\left(x+3\right)=2$

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dessinemoie
$\mathrm{log}2\left(x+2\right)-3\cdot \mathrm{log}8\left(x+3\right)=2$

$\mathrm{log}2\left(x+2\right)-\mathrm{log}2\left(x+3\right)=2$
$\mathrm{log}2\left[\frac{x+2}{x+3}\right]=2$
thus, $\frac{x+2}{x+3}={2}^{2}=4$
x+3=4*(x+3)
x+3=4x+12
3x=3-12=-9
x=-3