# log10^x = 2a and log10^y = b/2 write 10^a in terms of x

${\mathrm{log}10}^{x}=2a\phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}{\mathrm{log}10}^{y}=\frac{b}{2}$ write ${10}^{a}$ in terms of x
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casincal

so you havr $\mathrm{log}10\left({10}^{x}\right)=2a$
if so, you have$x=2a$ or $a=\frac{x}{2}$
$\mathrm{log}10\left({10}^{y}\right)=\frac{b}{2}$ become $y=\frac{b}{2}$ or $b=2×y$
${10}^{a}={10}^{\frac{x}{2}}$