# log10^x = 2a and log10^y = b/2 write 10^a in terms of x

Question
Logarithms
$$\displaystyle{{\log{{10}}}^{{x}}=}{2}{a}{\quad\text{and}\quad}{{\log{{10}}}^{{y}}=}\frac{{b}}{{2}}$$ write $$\displaystyle{10}^{{a}}$$ in terms of x

2021-02-02
so you havr $$\displaystyle{\log{{10}}}{\left({10}^{{x}}\right)}={2}{a}$$
if so, you have x=2a or a=x/2ZSK
$$\displaystyle{\log{{10}}}{\left({10}^{{y}}\right)}=\frac{{b}}{{2}}$$ become $$\displaystyle{y}=\frac{{b}}{{2}}$$ or b=2*y
1$$\displaystyle{0}^{{a}}={10}^{{\frac{{x}}{{2}}}}$$

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