so you havr \(\displaystyle{\log{{10}}}{\left({10}^{{x}}\right)}={2}{a}\)

if so, you have x=2a or a=x/2ZSK

\(\displaystyle{\log{{10}}}{\left({10}^{{y}}\right)}=\frac{{b}}{{2}}\) become \(\displaystyle{y}=\frac{{b}}{{2}}\) or b=2*y

1\(\displaystyle{0}^{{a}}={10}^{{\frac{{x}}{{2}}}}\)

if so, you have x=2a or a=x/2ZSK

\(\displaystyle{\log{{10}}}{\left({10}^{{y}}\right)}=\frac{{b}}{{2}}\) become \(\displaystyle{y}=\frac{{b}}{{2}}\) or b=2*y

1\(\displaystyle{0}^{{a}}={10}^{{\frac{{x}}{{2}}}}\)