# How to derive sin &#x2061;<!-- ⁡ --> ( 2 x ) = 1 <msqrt>

How to derive $\mathrm{sin}\left(2x\right)=\frac{1}{\sqrt{1+{\mathrm{cot}}^{2}\left(2x\right)}}$?
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Hint:
$1+{\mathrm{cot}}^{2}x=1+\frac{{\mathrm{cos}}^{2}x}{{\mathrm{sin}}^{2}x}=\frac{{\mathrm{sin}}^{2}x+{\mathrm{cos}}^{2}x}{{\mathrm{sin}}^{2}x}=\frac{1}{{\mathrm{sin}}^{2}x}$