A manager must form a team of 5 from among 5 employees from group A and 6 employees from group B. If

Despiniosnt

Despiniosnt

Answered question

2022-05-21

A manager must form a team of 5 from among 5 employees from group A and 6 employees from group B. If all employees have an equal chance of being selected, what is the approximate probability that a randomly selected group of 5 will consist of 2 employees from group A and 3 employees from group B?

Answer & Explanation

a2g1g9x

a2g1g9x

Beginner2022-05-22Added 12 answers

There are ( 5 + 6 5 ) = 462 equally likely ways of choosing the team of five from the eleven people
Of these, there are ( 5 2 ) ( 6 3 ) = 10 × 20 = 200 ways of choosing two from the As and three from the Bs
So the probability is 200 462 0.4329
Is this the "fairly complex combinatorics solution"?
Brennen Fisher

Brennen Fisher

Beginner2022-05-23Added 3 answers

Yes, this was the solution I was looking for and you have presented in a very clarified manner

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