Given a point on a hyperbolic paraboloid, prove that there

Chaz Blair

Chaz Blair

Answered question

2022-05-21

Given a point on a hyperbolic paraboloid, prove that there exist exactly 2 lines that pass through that point and lie on the surface of that paraboloid.

Answer & Explanation

soymmernenx

soymmernenx

Beginner2022-05-22Added 10 answers

Step 1
Let
x 2 a 2 y 2 b 2 = z
be the equation of the Hyperbolic Paraboloid (HP in short).
Consider the following family of lines with non zero parameter c
( L c )   { x a y b = c x a + y b = z c x 2 a 2 y 2 b 2 = z
(the implication is obtained by multiplying the equations)
But implication means for corresponding sets, inclusion. In this way, we have proven that
( L c ) ( H P ) .
Same reasoning for the other (distinct) family:
( L d )   { x a + y b = d x a y b = z d
Ashly Harrell

Ashly Harrell

Beginner2022-05-23Added 4 answers

BTW, The 2 lines are geodesics, unique euclidean straight lines for
x 2 a 2 y 2 b 2 = 2 z .

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