How do I express 14/(3-√2) in the form of b+c√d? I

Despiniosnt

Despiniosnt

Answered question

2022-05-20

How do I express 14/(3-√2) in the form of b+c√d?
I don't really understand the method to express a surd. Can anyone help me with this question? I really want more ideas on how to solve it, maybe there is one I may understand well. TY

Answer & Explanation

vard6vv

vard6vv

Beginner2022-05-21Added 12 answers

It's called rationalizing the denominator. This website actually has an example similar to your problem.
14 3 2 = 14 ( 3 + 2 ) ( 3 2 ) ( 3 + 2 ) = 42 + 14 2 7 = 6 + 2 2
Nylah Burnett

Nylah Burnett

Beginner2022-05-22Added 1 answers

Q [ 2 ] is a field (with the usual definitions of + and ).
What that means is that you can add, subtract, multiply, and divide two numbers of the type a + b 2 and you'll get another number of that type.
For your specific problem, first notice that ( c + d 2 ) ( c d 2 ) = c 2 2 d 2 is just a rational number (it is also of the form a + b 2 , where b = 0).
So then we have the idea that if we want to get a number of the form c + d 2 out of the denominator, we can just multiply it by c d 2 so that it becomes a regular rational number.
Let's try it:
14 3 2 = 14 3 2 ( 1 ) = 14 3 2 ( 3 + 2 3 + 2 ) = 42 + 14 2 7 = 6 + 2 2

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