Factorising this formula I came across this simplification in an iTunes U calculus course.

Loreenwk

Loreenwk

Answered question

2022-05-21

Factorising this formula
I came across this simplification in an iTunes U calculus course.
1 x 0 + δ x 1 x 0 δ x = 1 δ x ( x 0 ( x 0 + δ x ) ( x 0 + δ x ) x 0 )
I didn't understand how this was done. I can see the denominator being taken out for 1 δ x but do not understand the remainder. Can someone give me some guidance? Thanks

Answer & Explanation

Giovani Hickman

Giovani Hickman

Beginner2022-05-22Added 6 answers

It is
1 a 1 b = b a a b .
So, if a = x 0 + δ x and b = x 0 you have
1 x 0 + δ x 1 x 0 = x 0 ( x 0 + δ x ) x 0 ( x 0 + δ x ) .
prensistath

prensistath

Beginner2022-05-23Added 4 answers

Basically it is taking the same denominator:
1 a 1 b = b a b a a b = a b a b .
In the special case a = x 0 , b = x 0 + δ x

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