Nuclear fission equation Should not the energy conservation physics equation be E = &#

Yaritza Oneill

Yaritza Oneill

Answered question

2022-05-19

Nuclear fission equation
Should not the energy conservation physics equation be
E = m c 2  instead of  E = m c 2
because energy appears simultaneously with mass disappearance in splitting as
| Δ E | = | Δ m | c 2 ?
Also what in Einstein's derivation dispenses with the factor 1 2 from the usual kinetic energy
K E = 1 2 m v 2 ?
Sorry about the elementary question, it remained with me for longtime.

Answer & Explanation

verrainellewtzri

verrainellewtzri

Beginner2022-05-20Added 12 answers

About your first question:
E = m c 2 is not an equation that expresses energy conservation. It is an equation that relates the energy content of a physical object to its gravitating/inert mass. So for example, the equation says that, if you have a box filled with say some springs and a cold cup of tea and you open it, compress the springs and heat up the tea, adding some amount of energy Δ E to the system before closing the box again, then the mass of the box will increase by Δ E / c 2
Concerning your second question:
The classical kinetic energy term arises from the relativistic energy as the leading term in the Taylor approximation that is valid for small momentum/velocity. The factor of 1/2 has its origin in the Taylor expansion of the square root. There are two ways to approach the problem. My preferred view is that the m in your equation is the rest mass and the full relativistic energy momentum equation should be:
E = m 2 c 4 + p 2 c 2
where p is momentum.
There are also some heretical texts that introduce a so called "relativistic mass" m which is m = γ m 0 where m 0 is the rest mass. In this sacrilegious notation, E = m c 2 is also valid outside of the rest frame of the object that you are studying and the kinetic energy term arises from a Taylor expansion of the γ factor.

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