A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 rad/s . If the horizontal component of earth’s magnetism is 2 × 10 − 5 T, then voltage developed between the two ends of the conductor is ?

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A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 rad/s . If the horizontal component of earth’s magnetism is   2  ×      10          −      5        T, then voltage developed between the two ends of the conductor is ?

hospitaliapbury · Accepted Answer

Step 1Given in question - Length of rod (L) = 1 mAngular velocity(  ω) = 5 rad/sMagnetic field(B) =   2  ×      10          −      5       TeslaTo find -  Voltage developed between the two ends of the conductor.Solution; Step1 - Here, we will understand the concepts that will be used to solve this question.As we know that emf(Voltage) induced by a moving rod is given b formula -   V  =            B      ×      ω      ×              L        2              2    …  (  1  )Step 2- Put the given values in equation(1) to get the answer.  V  =            2      ×              10                  −          5                    ×      5      ×              1        2              2    =  5  ×      10          −      5           v  o  l  t  =  50  μ     v  o  l  tHence, induced voltage will be   50  μ     v  o  l  t

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 rad/s

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