# What is the polar form of (3, 27)?

What is the polar form of (3, 27)?
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Step 1
Polar form $=\left(r,\theta \right)$
$r=\sqrt{{3}^{3}+{27}^{2}}=\sqrt{9+729}=\sqrt{738}=3\sqrt{82}$
$\mathrm{tan}\theta =\frac{27}{3}=9$
Step 2
$\theta ={\mathrm{tan}}^{-1}9={83.66}^{\circ }$
Polar cordinate $=\left(3\sqrt{82},{83.66}^{\circ }\right)$