let n is non-negative number so the equations ( x 2 </msup> + 1

jistefaftexia99kq6

jistefaftexia99kq6

Answered question

2022-05-14

let n is non-negative number so the equations ( x 2 + 1 ) 2 + n = y z + 1 ( y 2 + 1 ) 2 + n = z x + 1 ( z 2 + 1 ) 2 + n = x y + 1have ( x , y , z ) real solution.find all solutions for the non-negative n that make ( x , y , z ) are real numbers and find ( x , y , z ) also

Answer & Explanation

Bumanro5mv

Bumanro5mv

Beginner2022-05-15Added 9 answers

Hint: First argue why x,y,z must have same sign. Now subtract any one equations from the other and conclude that x=y=z is only possible solution. Substitute in anyone equation and find the solution.

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