How to solve for y in y 2 </msup> 2 </mfrac> + y =

Carley Haley

Carley Haley

Answered question

2022-05-16

How to solve for y in y 2 2 + y = x 3 3 + x 2 2 + c 1 ?

Answer & Explanation

hospitaliapbury

hospitaliapbury

Beginner2022-05-17Added 25 answers

Since
y 2 2 + y = x 3 3 + x 2 2 + c 1 1 2 ( y + 1 ) 2 1 2 = x 3 3 + x 2 2 + c 1
It follows
( y + 1 ) 2 = 2 ( x 3 3 + x 2 2 + c 1 ) + 1
Then
y = 1 ± 2 ( x 3 3 + x 2 2 + c 1 ) + 1

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