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Annabel Sullivan

Annabel Sullivan

Answered question

2022-05-17

How do I show that cos 2 A cos 2 B + cos 2 B cos 2 C + cos 2 C cos 2 A 4 ( cos 2 A + cos 2 B + cos 2 C )?
A , B , C be the angles of an acute triangle.
How should I approach this kind of "geometric inequalities"? I've considered substituting the cosines using the law of the cosines and then use the Ravi transformation to turn it into an algebraic one, but that seems too tedious and unlikely to yield any beautiful solution. Any hints will be appreciated!

Answer & Explanation

noruegezajl00y

noruegezajl00y

Beginner2022-05-18Added 13 answers

By AM-GM easy to show that x y + y z + z x x + y + z x y z 3 for all positives x, y and z and
cos α cos β cos γ 1 8
Hence, c y c cos 2 α cos 2 β cos 2 α + cos 2 β + cos 2 γ cos 2 α cos 2 β cos 2 γ 3 4 ( cos 2 α + cos 2 β + cos 2 γ ) . Done!

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