Energy vs wavelength relation is given by, E ( e V ) = 1241 n m

Sappeycuii

Sappeycuii

Answered question

2022-05-14

Energy vs wavelength relation is given by, E ( e V ) = 1241 n m . Energy of H-atom in the ground state is -13.6eV as form the relation E ( e V ) = 13.6 Z e f f 2 n 2 ( e V ). Find that in which transition on hydrogen atom is the wavelength 486.1 nm produced? To which seriesdoes it belong ?

Answer & Explanation

Kaylin Barry

Kaylin Barry

Beginner2022-05-15Added 11 answers

Solution:
The energy corresponding to the given wavelength is calculated as;
E = 1241 486.1 = 2.55 × 10 9   e V
This energy corresponds to the beta Balmer series. This spectrum occurs when there is a transition from n=4 to n=2. Thus, this wavelength corresponds to the Balmer series.

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