Energy vs wavelength relation is given by, E ( e V ) = 1241 n m

Sappeycuii 2022-05-14 Answered
Energy vs wavelength relation is given by, E ( e V ) = 1241 n m . Energy of H-atom in the ground state is -13.6eV as form the relation E ( e V ) = 13.6 Z e f f 2 n 2 ( e V ). Find that in which transition on hydrogen atom is the wavelength 486.1 nm produced? To which seriesdoes it belong ?
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Answers (1)

Kaylin Barry
Answered 2022-05-15 Author has 12 answers
Solution:
The energy corresponding to the given wavelength is calculated as;
E = 1241 486.1 = 2.55 × 10 9   e V
This energy corresponds to the beta Balmer series. This spectrum occurs when there is a transition from n=4 to n=2. Thus, this wavelength corresponds to the Balmer series.
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