Calculate the energy of the first 4 photons emitted in

deformere692qr

deformere692qr

Answered question

2022-05-15

Calculate the energy of the first 4 photons emitted in the balmer series of the hydrogen spectrum. The Balmer series corresponds to nf=2 and the first 4 photons are the lowest energy transitions from higher energy levels. These 4 photons all hvae a wavelength in the visible spectrum.

Answer & Explanation

Raelynn Parker

Raelynn Parker

Beginner2022-05-16Added 12 answers

To find : The energy of first 4 photons emitted in balmer series of hydrogen spectrum
Using the formula for energy of n t h orbit of hydrogen :
E n = 13.6 n 2 e V E 2 = 13.6 4 e V = 3.4 e V E 3 = 13.6 9 e V = 1.51 e V E 4 = 13.6 16 e V = 0.85 e V E 5 = 13.6 25 e V = 0.544 e V E 6 = 13.6 36 e V = 0.377 e V
A) Energy of first photon of balmer series
= E 3 E 2 = 1.51 ( 3.4 ) e V = 1.89 e V
B) Energy of second photon of balmer series = E 4 E 2 = 0.85 ( 3.4 ) e V = 2.55 e V
C)Energy of third photon of balmer series = E 5 E 2 = 0.544 ( 3.4 ) e V = 2.856 e V
D) Energy of fourth photon of balmer series = E 6 E 2 = 0.377 ( 3.4 ) e V = 3.02 e V

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