so my task is to find out if the random variables defined by X n </msub> ( t

uto2rimxrs50

uto2rimxrs50

Answered question

2022-05-15

so my task is to find out if the random variables defined by X n ( t ) = n ( t ) n with t [ 0 , 1 ] converges almost surely against another random variable X in the probability space ( [ 0 , 1 ] , B [ 0 , 1 ] , λ [ 0 , 1 ] ). In a first step I tried to find X by calculating lim n X n ( t ), which gives me the following:
X = { 0 , 0 t < 1 ± , t = 1
So my question now is if it's even possible for this sequence of random variables to converge at all. I would say no but I'm not sure though cause 1 is a null set for the Lebesgue measure. If I'm correct is it, therefore, ok to conclude that any sequence of random variables with no unique limit function doesn't converge for any probability measure?

Answer & Explanation

TettetoxDetnhte5

TettetoxDetnhte5

Beginner2022-05-16Added 15 answers

Your calculations are correct, and you can conclude that ( X n ) converges almost surely to X by using the definition :
λ [ 0 , 1 ] ( lim n X n = X ) = λ [ 0 , 1 ] ( t [ 0 , 1 ] : lim n X n ( t ) = X ( t ) ) = λ [ 0 , 1 ] ( [ 0 , 1 [ ) = 1

So ( X n ) converges almost surely to the 0 (constant) random variable.

You are right to be concerned about the "ill-behaved" t = 1 case, where X n oscillates to infinity, but as it has measure zero, the convergence of the sequence ( X n ) is not affected.
lasquiyas5loaa

lasquiyas5loaa

Beginner2022-05-17Added 4 answers

Thank you for the response, i really appreciate it.

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