# Calculating appropriate arithmetic mean, median and peak values for equal data group. a) Body weights (kg) of patients who come to a nutrition clinic:

fortdefruitI 2020-11-09 Answered
Calculating appropriate arithmetic mean, median and peak values ​​for equal data group. a) Body weights (kg) of patients who come to a nutrition clinic: 50, 55, 69, 58, 57, 62, 60 b) Height measurements (cm) of children receiving treatment in the pediatric clinic: 120,125, 110, 105, 125, 108, 115, 125, 119 c) Blood urea level (mg / dl): 119, 5, 2, 6, 4, 3, 1 d) In which of the above distributions, arithmetic mean and peak value in hagi are not appropriate center criteria? Why is that?
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## Expert Answer

okomgcae
Answered 2020-11-10 Author has 93 answers
Since your question has multiple sub-parts, we will solve first three sub-parts for you. If you want remaining sub-parts to be solved, then please resubmit the whole question and specify those sub-parts you want us to solve. Part a: Body weight: The mean is computed as, $Mean=\frac{50+55+69+58+57+62+60}{7}$
$=\frac{411}{7}$
$=58.7143$ Thus, the mean is 58.7143. The median is the middle most value when observations are arranged in ascending order. Thus, we have observations in ascending order as 50,55,57,58,60,62,69. Hence, middle most observation is the ${4}^{t}h$ observation. Hence, median = 58. Peak value =maximum value = 69. Part b: Height The mean is computed as, $Mean=\frac{120+125+110+105+125+108+115+125+119}{9}$
$=\frac{1052}{9}$
$=116.8889$ Thus, the mean is 116.8889. The median is the middle most value when observations are arranged in ascending order. Thus, we have observations in ascending order as 105,108,110,115,119,120,125,125,125. Hence, middle most observation is the ${5}^{t}h$ observation. Hence, median = 119. Peak value =maximum value = 125 Part c: Blood urea level: The mean is computed as, $Mean=\frac{119+5+2+6+4+3+1}{7}$
$=\frac{140}{7}$
$=20$ Thus, the mean is 20. The median is the middle most value when observations are arranged in ascending order. Thus, we have observations in ascending order as 1,2,3,4,5,6,119. Hence, middle most observation is the ${5}^{t}h$ observation. Hence, median = 4. Peak value =maximum value = 119.
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