Complex proof - Not sure where to go from here. (homework) Knowing 2 &#x03C0;<!-- π --> r

Kiersten Hodge

Kiersten Hodge

Answered question

2022-05-11

Complex proof - Not sure where to go from here. (homework)
Knowing 2 π r = h m ( e 2 m r )
How do I prove r = h 2 ( ( 2 π ) 2 m e 2 ) ?
I started by dividing both sides by 2 π to get
r = h m ( e 2 m r ) 2 π
then I squared both sides to get
r 2 = h 2 m 2 ( e 2 m r ) ( 2 π ) 2
But I am not sure where to go from here to yield my expected result.
All help is appreciated.

Answer & Explanation

percolarse2rzd

percolarse2rzd

Beginner2022-05-12Added 17 answers

r 2 = h 2 m 2 ( e 2 m r ) ( 2 π ) 2
r 2 = h 2 m ( e 2 r ) ( 2 π ) 2
r 2 = r h 2 m ( e 2 ) ( 2 π ) 2
Multiply by 1 r both sides
r = h 2 m ( e 2 ) ( 2 π ) 2
Spencer Lutz

Spencer Lutz

Beginner2022-05-13Added 6 answers

r 2 = h 2 m 2 ( e 2 m r ) ( 2 π ) 2
r 2 = h 2 ( m e 2 r ) ( 2 π ) 2
4 π 2 r 2 = h 2 ( m e 2 r )
4 π 2 r 2 = r h 2 m e 2
4 π 2 r 2 m e 2 = r h 2
4 π 2 r 2 m e 2 r h 2 = 0
r ( 4 π 2 r m e 2 h 2 ) = 0
r = 0 , r = h 2 4 π 2 m e 2 = h 2 ( ( 2 π ) 2 m e 2 )
r > 0 probably (in your context) so you can reject the solution r = 0

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