Find the integral: ∫ 1 2 t 2 − 6 t + 1 d t.

Multiply&nbsp;12t2-6t+1&nbsp;by&nbsp;2t2-6t+12t2-6t+1.12t2-6t+1⋅2t2-6t+12t2-6t+1Combine and simplify the denominator.2t2-6t+12t2-6t+1&nbsp;

Question: "Find the integral: ∫ 1 2 t 2..."

dresu9dnjn

2022-04-10

Find the integral:

\int \frac{1}{\sqrt{2 t^{2} - 6 t + 1}} d t

Ellie Meyers

Beginner2022-04-11Added 15 answers

Multiply $\frac{1}{\sqrt{2 t^{2} - 6 t + 1}}$ by $\frac{\sqrt{2 t^{2} - 6 t + 1}}{\sqrt{2 t^{2} - 6 t + 1}}$ .

$\frac{1}{\sqrt{2 t^{2} - 6 t + 1}} \cdot \frac{\sqrt{2 t^{2} - 6 t + 1}}{\sqrt{2 t^{2} - 6 t + 1}}$

Combine and simplify the denominator.

$\frac{\sqrt{2 t^{2} - 6 t + 1}}{2 t^{2} - 6 t + 1}$

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