Find the integral: − 2 <msqrt> − x 2

poklanima5lqp3

poklanima5lqp3

Answered question

2022-05-12

Find the integral: 2 x 2 5 x + 1  d x.

Answer & Explanation

arbotsck8sg

arbotsck8sg

Beginner2022-05-13Added 22 answers

Multiply 2-x2-5x+1 by -x2-5x+1-x2-5x+1.

-(2-x2-5x+1-x2-5x+1-x2-5x+1)

Combine and simplify the denominator.

-2-x2-5x+1-x2-5x+1

Factor -1 out of -x2.

-2-x2-5x+1-(x2)-5x+1

Factor -1 out of -5x.

-2-x2-5x+1-(x2)-(5x)+1

Factor -1 out of -(x2)-(5x).

-2-x2-5x+1-(x2+5x)+1

Rewrite 1 as -1(-1).

-2-x2-5x+1-(x2+5x)-1(-1)

Factor -1 out of -(x2+5x)-1(-1).

-2-x2-5x+1-(x2+5x-1)

Simplify the expression.

2-x2-5x+1x2+5x-1
 

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