Given f ( x ) = 1 4 </mfrac> ( x + 4 ) 2

Defensorentx9

Defensorentx9

Answered question

2022-05-10

Given f ( x ) = 1 4 ( x + 4 ) 2 2
Find: vertex, y-intercept, x-intercepts (if any), axis of symmetry
What I have so far:
Vertex: ( 4 , 2 )
y-intercept: ( 0 , 2 )
x-intercept: 2
Axis of symmetry x = 4

Answer & Explanation

gudstrufy47j

gudstrufy47j

Beginner2022-05-11Added 16 answers

Consider y = a ( x + 4 ) 2 2. Let Y = y + 2 and X = x + 4. Then Y = a X 2 .
This means that the curve y = a ( x + 4 ) 2 2 is a translation of the curve Y = a X 2 : the origin ( 0 , 0 ) in X Y-space goes to the point ( 4 , 2 ) in x y-space.
Thus, the vertex of y = a ( x + 4 ) 2 2 is at ( 4 , 2 ), the symmetry axis is x = 4, etc.
uto2rimxrs50

uto2rimxrs50

Beginner2022-05-12Added 2 answers

Everything is right except for the x intercept(s). Try moving the -2 to the Left Side, and then simplyfying to get x in terms of square roots.

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