In orthodox probability theory, only certain trivial Boolean algebras with very few elements contain

Aedan Tyler

Aedan Tyler

Answered question

2022-05-08

In orthodox probability theory, only certain trivial Boolean algebras with very few elements contain, for any given A and B, an event X which satisfies P(X) = P(B|A). Later extended by others, this result stands as a major obstacle to any talk about logical objects that can be the bearers of conditional probabilities.
I'm aware that in Bayesian analysis, the conditional likelihood P(B|A) is not a probability distribution. There must be a connection here right? What are some simple examples of conditional events that are not in the event algebra?

Answer & Explanation

Jerry Kidd

Jerry Kidd

Beginner2022-05-09Added 18 answers

"in orthodox probability theory, only certain trivial Boolean algebras with very few elements contain, for any given A and B, an event X which satisfies P(X) = P(B|A)."
On ( Ω , F , P ) = ( [ 0 , 1 ] , B ( [ 0 , 1 ] ) , L e b ), for every A and B, there exists an event X such that P ( X ) = P ( B A ) (as soon as the RHS exists): pick X = [ 0 , x ] where x = P ( B A ).
"...in Bayesian analysis, the conditional likelihood P(B|A) is not a probability distribution..."
When it exists, the mapping P (   A ) is very much a probability measure.
"What are some simple examples of conditional events that are not in the event algebra?"
Define "conditional event".

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