An airline will fill 100 seats of its aircraft at a fare of 200 dollars. For every 5 dollar increase

syaoronsangelhwc17

syaoronsangelhwc17

Answered question

2022-05-08

An airline will fill 100 seats of its aircraft at a fare of 200 dollars. For every 5 dollar increase in the fare, the plane loses two passengers. For every decrease of $5, the company gains two passengers. What price maximizes revenue?
I'm a bit lost as to what my equations should be. The total revenue, if all seats are filled can be 20000. So for every 5 dollar increase the total revenue becomes: 20000−400x (400x = 2 people time the price of each ticket times the number of 5 dollar increases). I don't know how to model the other situation of a 5 dollar decrease.

Answer & Explanation

bamenyab4mxn

bamenyab4mxn

Beginner2022-05-09Added 16 answers

The first part of solving such a problem is to make some definitions. Without definitions for a word-problem one doesn't get anywhere.

1. The amount of dollars a ticket costs is x
2. The number of passengers will be a function, let us call it f ( x )
3. The total revenue will be a function, let us call it g ( x )

Now you can start tying to figure out the relations between these. And once you have found f ( x ) and g ( x ) that's when you can use your knowledge of the derivative and how you can use it.

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