Antiderivative around inverse trigonometric function I'm just learning about antiderivative that re

pevljivuaosyc

pevljivuaosyc

Answered question

2022-05-08

Antiderivative around inverse trigonometric function
I'm just learning about antiderivative that resulted some inverse trigonometric functions, since derivative of arccos ( x ) is 1 1 x 2 . I tried put this value back into integral calculator, but I got arcsin ( x ) instead of arccos ( x ). even though arcsin ( x ) arccos ( x ) so why this happen? How should I fix my understanding?

Answer & Explanation

Cara Cannon

Cara Cannon

Beginner2022-05-09Added 14 answers

Explanation:
That's because arcsin ( x ) + arccos ( x ) = π 2 and π / 2 is a constant.
When integrating, always remember that there's a constant C in the result.

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